函数y=sinx+根号3cosx,x属于[π⼀6,π]的值域是?要具体过程!谢谢

2025-12-24 18:21:58
推荐回答(1个)
回答1:

y=sinx+√3cosx
y=2sin(x+π/3)
x∈[π/6,π]
-√3<=y<=2
y∈[-√3,2]