等差数列中,a1=20 ,an=54,sn=888,求n与d

2025-12-25 08:18:23
推荐回答(4个)
回答1:

n=2Sn/(a1+an)=2×888÷(20+54)=24
d=(an-a1)/(n-1)=(54-20)÷(24-1)=34/23

回答2:

sn=(a1+an)/2*n=888
(20+54)/2*n=888
n=24
an=a1+(n-1)d=54
20+23d=54
d=34/23

回答3:

n=24.d=34/23

回答4:

n=24, d=34/23